NTSE MATHS#5
Geometry
Level
3
A circle with area A cm^2 is contained in the interior of a larger circle with area (A+B) cm^2 and radius of the larger circle is 4 cm. If A, B, A+B are in AP, then diameter(in cm) of the smaller circle is
[3^(1/2)] / 2
8 / [ 3^(1/2)]
4 / [3^(1/2)]
2 * [3^(1/2)]
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1 solution
A,B,A+B in AP
2A+B=2B
2A=B
area of larger circle=16*(22/7)
3A=16*(22/7)
area of smaller circle=A
So radius =[16/3]^(1/2)= 4/[3^(1/2)]