Nuclear physics problem No.1

Chemistry Level 2

A sample of rock contains two isotopes of uranium 92 235 U \displaystyle ^{235}_{92}U and 92 238 U \displaystyle ^{238}_{92}U , with the ratio of 92 235 U \displaystyle ^{235}_{92}U particles and 92 238 U \displaystyle ^{238}_{92}U particles is R = 3 100 \displaystyle R = \frac{3}{100} . Calculate how long it will take so that R = 7 1000 \displaystyle R' = \frac{7}{1000} , know that the half life periods of two isotopes 92 235 U \displaystyle ^{235}_{92}U and 92 238 U \displaystyle ^{238}_{92}U is T 235 = 0.7 × 1 0 9 \displaystyle T_{235}=0.7 \times 10^{9} years and T 235 = 4.5 × 1 0 9 \displaystyle T_{235}=4.5 \times 10^{9} years.

Answer comes in billion years , rounds up to 3 decimal places.


The answer is 1.740404571.

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1 solution

F Zs
Jun 11, 2021

The amount of not-decayed particles is given by the

n × 2 t t h n \times 2^{-\frac t{t_h}}

exponential equation, where n n is the amount of particles at t = 0 t = 0 , t t is the time passed and t h t_h is the halving time of the particles.

By substituting data into this formula, we get to functions, one for each isotope:

f 235 ( t ) = 3 × 2 t 0.7 1 0 9 f_{235}(t) = 3 \times 2^{-\frac t{0.7 \cdot 10^9}} f 238 ( t ) = 100 × 2 t 4.5 1 0 9 f_{238}(t) = 100 \times 2^{-\frac t{4.5 \cdot 10^9}}

From that, we can calculate the ratio of the two isotopes at any time point:

R ( t ) = f 235 ( t ) f 238 ( t ) R(t) = \frac{f_{235}(t)}{f_{238}(t)}

All we need to do now is substitute 7 1000 \frac7{1000} in the place of R R .

By solving the equation, we get that

t = 1740404571.50 \boxed{t = 1740404571.50}

Here's this explanation visualized on GeoGebra

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