Let be a 3-digit positive integer and let be another 3-digit positive integer obtained by reversing the digits of .
Find the number of possible values of such that .
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L e t N = 1 0 0 x + 1 0 y + z , S o M = 1 0 0 z + 1 0 y + x ⇒ N − M = 9 9 ( x − z ) = 3 9 6 x − z = 4 , S o p o s s i b l e v a l u e s o f ( x , z ) → ( 5 , 1 ) , ( 6 , 2 ) , ( 7 , 3 ) , ( 8 , 4 ) & ( 9 , 5 ) N o w f o r a n y v a l u e o f ( x , y ) t h e r e a r e 1 0 v a l u e s o f y ( 0 − 9 ) H e n c e t h e r e a r e 5 × 1 0 = 5 0 p o s s i b l e v a l u e s .