Number 3

$4 × \overline { ABCD } = \overline {DCBA}$

$4 × \overline {ABCD} ≥ 9999 → \overline {ABCD} ≥ 2499$

Then $A ≤ 2$

$4D \equiv A\pmod{10}.$

A is even $→ A = 2$

$4D \equiv 2\pmod{10}$ $→$ $D \equiv 3\pmod{5}$

$D = 3$ or $D=8$

$4 × \overline {2BCD} = \overline {DCBA} ≥ 8000$ $→ D = 8$

$4 (2000 + 100B + 10 C + 8) = 8000 + 100C + 10 B + 2$

$8000 +40B + 40C + 32 = 8000 + 100C + 10 B + 2$

$13B = 2C - 1$

$2C -1 1 ≤ 17$ $→ 13B ≤ 17$

$B = 0$ or $B = 1$

$4\mid \overline {DCBA}$ $→$ $4\mid \overline {B2}$ $→ B = 1$

$13 = 2C - 1$ $→ C = 7$

Finally $4 (2178) = 8712$