How many integers that are multiples of 3 are there between 1,000 and 1,000,000?
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First multiple of 3 between 1000 and 1000000 = a = 1002
Last multiple = l = 999999
d = 3
l = a + (n-1)d
999999 = 1002 + (n-1)*3
n = 333000
999,999 - 1,002 = 998,997/3 + 1 = 333,000
arithmetic sequence a + (n-1)b 1002 + (n-1)3 = 999999
1002 + 3n - 3 = 999999
999 + 3n = 999999
3n = 999999-999
n = = 333000
arithmetic sequence
a + (n-1)b
1002 + (n-1)3 = 999999
1002 + 3n - 3 = 999999
999 + 3n = 999999
3n = 999999-999
n = 3 9 9 9 0 0 0 = 333000
3 1 , 0 0 0 , 0 0 0 - 3 1 , 0 0 0 <<< use the whole number only
333,333 - 333 = 333,000
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1000000-1000=999000 999000/3=333000