Number Brain

Let the two numbers be $x$ and $y$ .
Now , According to Question.

$\Rightarrow x-y=2$ ..... $(1)$

$\Rightarrow x^2-y^2=6$

$(x+y)(x-y)=6$

From $(1)$ .

$(x+y)(2)=6$

$\therefore x+y=\boxed{3}$

$x-y=2$ $\implies$ $\boxed{1}$

$x^2-y^2=6$ $\implies$ $\boxed{2}$

$x^2-y^2=(x-y)(x+y)$

$6=(2)(x+y)$

$x+y=$ $\boxed{3}$

Assume, the two number is $x$ and $y$ . So $x-y = 2$ and $x^2 - y^2 = 6$

$x^2 - y^2 = 6$

$( 2 + y)^2 - y^2 = 6$

$4 + 4y+ y^2 - y^2 = 6$

$4y-2 = 0$

$4y = 2$

$y = \frac{1}{2}$

We have found $y$ , now to find $x$ ,

$x=2 + y$

$x= 2 +\frac{1}{2}$

$x = 2\frac{1}{2}$

Now we sum it

$x+ y = 2\frac{1}{2} + \frac{1}{2} = 3$