Number of elements in a set

Algebra Level 2

If A , B A, B and C C are three sets such that

∣ A ∣ = 25 , ∣ B ∣ = 20 , ∣ C ∣ = 27 , ∣ A ∩ B ∣ = 5 , ∣ B ∩ C ∣ = 7 , A ∩ C = ∅ . , \begin{array}{c}& \lvert A \rvert=25, & \lvert B \rvert=20, & \lvert C \rvert=27,\\ \lvert A\cap B \rvert=5, & \lvert B\cap C \rvert=7, & A\cap C=\emptyset. \end{array},

what is ∣ A ∪ B ∪ C ∣ ? \lvert A \cup B \cup C \rvert ?


The answer is 60.

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Lawahar Qasid by Lawahar Qasid

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1 solution

Dhirendra Singh
Jan 14, 2015

To get the right answer we just add the number of elements in set A,B and C and subtract the common elements means elements of intersection sets. So it is 25+20+27-5-7-0=60

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