Number of Perfect Squares

{ 1 1 , 2 2 , 3 3 , , 201 7 2017 } \Big\{1^1,\ 2^2,\ 3^3,\ \ldots,\ 2017^{2017}\Big\}

How many perfect squares are there in the above set?


The answer is 1030.

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1 solution

Steven Yuan
Jun 13, 2017

A number of the form x x , x^x, where x x is some positive integer, can be a perfect square if and only if either x x is even or x x is an odd perfect square. There are 1008 even integers between 1 and 2017 inclusive. To count the number of odd perfect squares in that interval, we realize that 4 4 2 44^2 is the greatest perfect square less than 2017. There are 22 odd integers between 1 and 44 inclusive, so there are also 22 odd perfect squares between 1 and 2017. Therefore, the number of perfect squares in the set is 1008 + 22 = 1030 . 1008 + 22 = \boxed{1030}.

I do not understand how 44^2=1936 will be included in the Odd Perfect squares, since 44 is an even number and the number is already included in the 1008 even integers.

Sivasis Dash - 3 years, 11 months ago

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I used 4 4 2 44^2 to give an upper bound for the value of an odd perfect square less than 2017, but of course that's not an odd perfect square - it's only an upper bound.

Steven Yuan - 3 years, 11 months ago

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