Consider a ternary sequence of length , consisting of symbols, each taken from the set . This sequence is to be transmitted over a power-constrained wireless link. Assume that the symbols takes unit of energy respectively, for transmission. Due to the power-constraint, only those sequences are eligible for transmission whose required average transmission energy is at most .
In other words, for a sequence , if the transmitted symbol consumes amount of energy, then the sequence is eligible for transmission if and only if As an explicit example, with , the sequences are eligible for transmission, but the sequence is not.
Let denote the number of eligible sequences of length . Define if the above limit exists, otherwise, define .
Find .
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At the outset, it looks like a difficult combinatorial problem. However, I'll show how probabilistic methods can be used to solve this problem (or even more general versions of it) very easily.
Consider a random sequence W of length n , each of whose elements W i are chosen i.i.d. with uniform probability, i.e. for each j = 0 , 1 , 2 and for all i = 1 , 2 , … , n P ( W i = j ) = 3 1 Thus probability of each sequence in { 0 , 1 , 2 } n is uniformly 3 − n .
We are interested in the probability that a randomly chosen sequence is eligible for transmission, i.e. P ( n 1 i = 1 ∑ n W i ≤ 2 1 ) By definition, the number of sequences N ( n ) of length n which are eligible for transmission, is simply N ( n ) = 3 n P ( n 1 i = 1 ∑ n W i ≤ 2 1 ) Thus, the required limit is l = n → ∞ lim n 1 ln N ( n ) = ln ( 3 ) + n → ∞ lim n 1 ln ( P ( n 1 i = 1 ∑ n W i ≤ 2 1 ) ) Thus, all we have to do is to evaluate the limit on the right hand side. Now, note that the random variables W i are chosen i.i.d. with uniform probability. Hence, we can simply use standard Large Deviation Theory for evaluating this limit. The Moment Generating Function of the i.i.d. random variables W i is M ( θ ) = E ( exp ( θ W i ) ) = 3 1 ( 1 + exp ( θ ) + exp ( 2 θ ) ) Hence, using the Large Deviation Theory, we have n → ∞ lim n 1 ln ( P ( n 1 i = 1 ∑ n W i ≤ 2 1 ) ) = − θ > 0 sup ( − 2 θ − ln M ( − θ ) ) ≈ ( ∗ ) − 0 . 1 9 7 3 7 8 , where (*) follows from simple calculus. Hence, it follows that ⌊ 1 0 4 l ⌋ = 9 0 1 2 .
Remark 1: The above method is very general and can be used to find such limits when we have a constraint of the form n 1 ∑ i = 1 n f ( w i ) ≤ α for virtually any function f .
Remark 2: Things usually behave nicely in the limit. That is why we have so many nice limit theorems in probability (Central Limit Theorem (CLT), Laws of Large Numbers (LLN), Law of Iterated Logarithms (LIL) and so on). It is a good exercise to use these limit theorems to get a first order approximation to many combinatorial problems, which might look daunting in their finite incarnations.