Number of sides

Geometry Level 1

The sum of the interior angles of a polygon with n n equal sides is 126 0 1260^\circ ? Find the number of sides.

9 8 7 10

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2 solutions

Noel Lo
Jul 10, 2017

Assuming the polygon is regular, each interior angles is of size 1260 n \frac{1260}{n} . This makes each exterior angle 180 1260 n 180-\frac{1260}{n} . Now the exterior angles of any polygon add up to 360 360 degrees so each exterior angle would be 360 n \frac{360}{n} . Therefore:

180 1260 n = 360 n 180-\frac{1260}{n}=\frac{360}{n}

180 n 1260 = 360 180n-1260=360

180 n = 1620 180n=1620

n = 9 n=\boxed{9}

In a polygon, the sum of interior angles is

s = ( n 2 ) ( 180 ) s=(n-2)(180)

Substituting, we get

1260 = ( n 2 ) ( 180 ) 1260=(n-2)(180)

Dividing both sides by 180 180 , we get

7 = n 2 7=n-2

Adding 2 2 to both sides, we get

9 = n 9=n

This is a good problem for the memory.

A Former Brilliant Member - 3 years, 7 months ago

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