Number of Terms in Expansion of Polynomial

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Let

P ( x ) = n = 1 10 ( x 2 n x 2 n 1 + 1 ) = ( x 2 x + 1 ) ( x 4 x 2 + 1 ) ( x 1024 x 512 + 1 ) . \begin{aligned}P(x)&=\displaystyle\prod_{n=1}^{10}\left(x^{2^n}-x^{2^{n-1}}+1\right)\\&=(x^2-x+1)(x^4-x^2+1)\ldots(x^{1024}-x^{512}+1).\end{aligned}

Let N N be the number of terms with non-zero coefficients when P ( x ) P(x) is expanded (including the constant term). What is the remainder when N N is divided by 1000 1000 ?


The answer is 365.

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1 solution

Dong kwan Yoo
Aug 17, 2017

sorry, latex is too difficult to me...T.T

3 sets are disjoint ( 2049/3 , 2048-1025/3 , 1024-1/3 )

∵ 2049/3 : exponent of x = 3k / 2048-1025/3 : exp = 3k+2 / 1024-1/3 : exp = 3k+1

Dong kwan Yoo - 3 years, 9 months ago

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