number of the digits :

Algebra Level pending

If you know that : X^10 = 10^10^10 .. Then find the number of the digits of ( x ) .

100000000001 1000000 10000000 10000001 1000000001 1000001

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

The number of the digits of ( 10^n ) = n+1 .. X^10 = 10^10^10 .. X = 10^10^9 .. the number of the digits of ( X ) = ( 10^9 ) + 1 = 1000000001 .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...