Number Pyramids

There are only 20 cases if we choose 3 numbers from 1,3,4,5,7,9.Only 7 cases produces composite numbers. $(1,3,9)\rightarrow39$ $(1,4,7)\rightarrow39$ $(1,4,9)\rightarrow49$ $(3,4,9)\rightarrow75$ $(3,5,9)\rightarrow87$ $(3,7,9)\rightarrow111$ $(5,7,9)\rightarrow143$ Notice the triple $(1,7,a)$ .Only $a=4$ fits,so $1$ and $7$ is on the second row.Let $1$ be on the left,and $7$ on the right.

Notice the triple $(5,b,c)$ . $1$ can't be adjacent to $5$ ,so $5$ must be on the bottom right corner.

Notice the bottom right triple $(5,7,d),d=9$ ,so the bottom middle number is $9$

So it should be like this $4\\1\quad{\tiny{39}}\quad7\\3\quad{\tiny{39}}\quad9\quad{\tiny{143}}\quad5$

$39+39+143=221$