Number theory!

t = n 3 n a , a 5 \large t=\frac{n^3}{n-a}, \quad a\leq 5

The above equation holds true for some positive integers t t , n n , and a a . Let S S be the sum of all distinct values of n n . Find ( S 1 ) (S-1) .


The answer is 333.

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1 solution

Kushal Bose
Jul 22, 2016

t = n 3 n a t=\dfrac{n^3}{n-a}

t = n 3 a 3 + a 3 n a t=\dfrac{n^3-a^3+a^3}{n-a}

t = n 2 + a n + a 2 t=n^2+an+a^2 + a 3 n a \dfrac{a^3}{n-a}

Now putting a=1,2,3,4,5 one can find the distinct values of n for which second part will be an integer

Values of n are 2,3,4,5,6,8,10,12,20,30,36,68,130

how did u plugged values of a

Adi Garg - 4 years, 10 months ago

Your second step is very nice.

Priyanshu Mishra - 4 years, 10 months ago

Did the same

Sayantan Saha - 4 years, 10 months ago

Why can't we substitute the values directly?

Racchit Jain - 4 years, 10 months ago

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