Number Theory + Co-ordinate Geometry = Challenging problems

Number Theory Level pending


The answer is 48.

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2 solutions

Saket Sharma
Sep 20, 2014

Given ( x 2 y 2 ) ( x 2 + y 2 ) = 175 (x^{2} - y^{2})(x^{2} + y^{2}) = 175 where, x & y are integers.

If x & y are integers each of the two terms on LHS are numbers. This implies RHS = 175 must be product of two numbers. This in turn implies we need to break it up into factors.

175 = 1 x 175 or 5 x 35 or 7 x 25

We further note that some of the two terms on LHS = 2 x 2 2x^{2} . This implies (sum of the two factors of 175)/2 must be a perfect square. This happens only with (7, 25).

Hence x 2 = ( 7 + 25 ) / 2 = 16 x^{2} = (7+25)/2 = 16 . This gives x = +4 or -4. Similarly one can obtain y = +3 or -3.

So, the rectangle formed has sides (4 - (-4)) = 8 and (3 - (-3)) = 6. Area = 8 x 6 = 48 sq unit.

Trevor Arashiro
Aug 12, 2014

The first step is to prime factorize 175 to 5,5,7.

We see that x 2 y 2 < x 2 + y 2 x^2-y^2<x^2+y^2 .

Thus x 2 y 2 = ( 5 , 7 ) x^2-y^2=(5,7)

We observe that 35 cant be written as the sum of two squares. Thus x 2 + y 2 = 25 x^2+y^2=25 . The only two integers that satisfy this are (x,y)=(4,3).

Finally, because the equation is centered at (0,0) the question asks us to find 4 x y = 4 ( 4 ) ( 3 ) = 48 4xy=4(4)(3)=\boxed{48} .

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