Number Theory#0

The number of 5 digit +ve integers that are divisible by 3 can be formed using the digits 0,1,2,3,4 and 5 without repeating any of the digits are


The answer is 216.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Stephen Mellor
Oct 20, 2017

A 5-digit number using those 6 digits with no repeats, means you must leave out 1 digit. The total of the digits is 15, a multiple of 3. Hence, it is also a multiple of 3 that is removed.

If the removed digit is 0, then there are 5 ! = 120 5! = 120 ways to arrange the digits. If the removed digit is 3, then there are only 4 × 4 ! = 96 4 \times 4! = 96 ways to arrange the digits as it can't have a leading zero.

Therefore, 120 + 96 = 216 120 + 96 = \boxed{216} is the answer

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...