In the triangle, each of the numbers is placed into a different circle. The sums of the numbers on each of the three sides of the triangle are equal to the same number . The sum of all of the different possible values of is ?
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This is as much as I can type in.
The numbers 1..8 add up to 36. Call the numbers in the corners a,b,c and their mean m. (Their sum is 3m)
Then 3s = 36 + 3m, because we have added the three corners twice.
So s = 12 + m
Also: m is between 2 and 7, inclusive (3m is between 6 and 21). In which case s is 14,15,16,17,18 or 19
But s=14 is impossible because m = 2 means (a,b,c) = (1,2,3) so the middle number on the base has to be atleast 9.
And s=18 is impossible, because that corresponds to m=6, requiring a+b+c = 18. This requires the middle number on the base to be the same as the number at the top.
15,16,17,19 are possible. (By construction)