Numbers

Four consecutive number can be written as

$a, a+1, a+2, a+3$

Since the sum of the first three is $100$ more than the last one we can say that

$a + (a+1) + (a+2) = (a+3) + 100$

This simplifies down to

$3a + 3 = a + 103$

Re-arranging this gives us a value for $a$

$a = 50$

So the sum of the four numbers comes to

$50 + 51 + 52 + 53 = 206$

The consecutive numbers can be written as follows: x, x+1, x+2, x+3 If the sum of the first 3 consecutive is a 100 more than the 4th, then x+x+1+x+2=x+3+100 x=50 Hence, the numbers are 50, 51,52,53