Observations of the ATM straddle price

On the week of expiry, you recorded the closing price of the ATM straddle as follows:

Trading days left 5 4 3 2
Price of Straddle 3.35 3.23 3.03 2.73

What can you conclude is happening?

The market is mispriced There is nothing wrong The volatility is increasing greatly Time is passing at a slower rate The stock price is increasing greatly The straddle approximation formula does not hold when t < 5 t < 5 days

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1 solution

Calvin Lin Staff
Feb 15, 2015

From the straddle approximation formula, Y = S σ t 2000 Y = \frac{ S \sigma \sqrt{t} } { 2000} . Thus, if the stock price and volatility stay constant, then the ratio of the price of the straddle should be 5 : 4 : 3 : 2 \sqrt{5} : \sqrt{4} : \sqrt{3} : \sqrt{ 2 } . As such, if the straddle price started out at 3.35, then the corresponding prices should have been 3.35 , 2.99.2.59 , 2.12 3.35, 2.99. 2.59, 2.12 .

We can see that the given prices are quite a bit higher than these calculated values, which implies that S σ S \sigma must be increasing.

Looking at the 3 days left and 2 days left, we see that S σ S \sigma have gone up by 17% and 29% respectively. It is somewhat unlikely that this is completely due to the stock price jumping up by those amounts, without seeing a great increase in volatility. Instead, the main reason for the price increase would be that the implied volatility of these options is increasing.

Such a scenario occurs when there is major news that is announced on the day of expiration of the straddle. In this case, the straddle is pricing in the expected movement on the last day, and that the volatility on the last day is much much higher than the volatility of the rest of the week.

this answer is a real stretch how did he discern the decay

ken hayes - 4 years, 5 months ago

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Check out the wiki on straddle approximation formula , which lists out the implications like the value of theta ATM.

Calvin Lin Staff - 4 years, 5 months ago

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