OCR A Level: Core 3 - Trigonomoetry [January 2006 Q9]

Geometry Level 4

( i ) (\text{i}) By first writing sin 3 θ \sin 3 \theta as sin ( 2 θ + θ ) \sin (2 \theta + \theta) , show that sin 3 θ = 3 sin θ 4 sin 3 θ . \sin 3 \theta = 3 \sin \theta - 4 \sin^3 \theta .

( ii ) (\text{ii}) Determine the greatest possible value of 9 sin ( 10 3 α ) 12 sin 3 ( 10 3 α ) 9 \sin \left (\dfrac{10}{3} \alpha \right )- 12 \sin^3 \left (\dfrac{10}{3} \alpha \right ) and find the smallest positive value of α \alpha (in degrees) for which that value occurs.

( iii ) (\text{iii}) Solve, for 0 ° < β < 90 ° 0°< \beta < 90° , the equation 3 sin 6 β csc 2 β = 4 3 \sin 6 \beta \, \text{csc} \, 2 \beta = 4 . Give your answer(s) to 3 significant figures.


Input the largest possible value of β \beta as your answer.


There are 4 marks available for part (i), 3 marks for part (ii) and 6 marks for part (iii).
In total, this question is worth 18.1% of all available marks in the paper.

This is part of the set OCR A Level Problems .


The answer is 69.9.

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1 solution

Michael Fuller
Mar 18, 2016

The mark scheme for this question: Large Version

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