OCR A Level: Further Pure 2 - Rectangle Approximation [January 2010 Q7]

Calculus Level pending

The diagram shows the curve y = x 3 y=\sqrt [ 3 ]{ x } , together with a set of n n rectangles of unit width.

( i ) (\text{i}) By considering the areas of these rectangles, explain why 1 3 + 2 3 + 3 3 + + n 3 > 0 n x 3 d x . \sqrt [ 3 ]{ 1 }+\sqrt [ 3 ]{ 2 }+\sqrt [ 3 ]{ 3 }+\cdots+\sqrt [ 3 ]{ n } > \int _{ 0 }^{ n }{ \sqrt [ 3 ]{ x } } \, dx . ( ii ) (\text{ii}) By drawing another set of rectangles and considering their areas, show that 1 3 + 2 3 + 3 3 + + n 3 < 1 n + 1 x 3 d x . \sqrt [ 3 ]{ 1 }+\sqrt [ 3 ]{ 2 }+\sqrt [ 3 ]{ 3 }+\cdots+\sqrt [ 3 ]{ n } < \int _{ 1 }^{ n+1 }{ \sqrt [ 3 ]{ x } } \, dx . ( iii ) (\text{iii}) Hence find an approximation to n = 1 100 n 3 \displaystyle \sum _{ n=1 }^{ 100 }{ \sqrt [ 3 ]{ n } } , giving your answer correct to 2 significant figures .


Input your answer to part ( iii ) (\text{iii}) .


There are 2 marks available for part (i), 3 marks for part (ii) and 3 marks for part (iii).
In total, this question is worth 11.1% of all available marks in the paper.

This is part of the set OCR A Level Problems .


The answer is 350.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Michael Fuller
Mar 8, 2016

The mark scheme for this question:
Large Version

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...