OCR A Level: Mechanics 2 - Projectile Motion [June 2008 Q4]

A golfer hits a ball from a point O O on horizontal ground with a velocity of 35 ms 1 35\text{ms}^{-1} at an angle of θ \theta above the horizontal. The horizontal range of the ball is R R and the time of flight is t t seconds.

( i ) (\text{i}) Express t t in terms of θ \theta , and hence show that R = 125 sin 2 θ R=125 \sin 2 \theta .

The golfer hits the ball so that it lands 110 m 110 \text{m} from O O .

( ii ) (\text{ii}) Calculate the two possible values of t t .


Input the sum of the two values of t t , correct to 3 significant figures


There are 5 marks available for part (i) and 5 marks for part (ii).
In total, this question is worth 13.9% of all available marks in the paper.

This is part of the set OCR A Level Problems .


The answer is 9.79.

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2 solutions

Michael Fuller
Mar 16, 2016

The mark scheme for this question: Large Version

Sudhir Aripirala
May 19, 2016

We know that, A particle suffers same range when it is projected with angle x or 90-x.

Also. The two values of time are (2usinx)/g and (2ucosx)/g . Now, R=(u)^2(sin2x)/(g)..

By substituting u=35m/s and g=9.8 we get

R=125sin2x..

By substituting R=110.. We get sin2x=22/25 from which we get x=0.537..

Sum of values of time= 2u(sinx+cosx)/(g)

By substituting u=35 and x=0.537.. and g=9.8

we get approximately 9.79..

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