Odd addition

Algebra Level 3

If the sum of the first 1 0 1 0 100 10^{10^{100}} odd numbers is of the form a b a \large a^{b^{a}} for positive integers a a and b b , find a + b a+b .


The answer is 110.

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1 solution

Chew-Seong Cheong
Mar 17, 2018

The sum of first n n odd number is given by S n = k = 1 n ( 2 k 1 ) = n ( n + 1 ) n = n 2 S_n = \displaystyle \sum_{k=1}^n (2k-1) = n(n+1) -n = n^2 . Therefore, for n = 1 0 1 0 100 n = 10^{10^{100}} , S n = ( 1 0 1 0 100 ) 2 = ( 1 0 2 ) 1 0 100 = 10 0 1 0 100 S_n = \left(10^{10^{100}}\right)^2 = \left(10^2\right)^{10^{100}} = 100^{10^{100}} . Hence a + b = 100 + 10 = 110 a+b=100+10=\boxed{110} .

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