Odd even love (beginners)

Even numbers are of the form $2k$

Odd numbers are of the form $2k + 1$

So, First Equation $→ (2k+1 \ + \ 2k+1) → 2(2k +1).$ thus, even

Second Equation $→ (2k \ + \ 2k+1) → 4k +1).$ thus, odd

Third Equation(Answer Equation) $→ (2k \ + \ 2k) → 2(2k) → 4k .$ thus, even

All even number can be written as product of $2$ by something

Let it be $m$ and $n$ even numbers which are can be written as $m=2k$ and $n=2s$ .

$m+n=2k+2s=2(k+s)\therefore$ $\text{even}+\text{even}=\text{even}$

Even is equal a 2k, k is integer. Therefore even + even = 2k + 2k = 4k, and 4k is 2x(2k) is even. Then even + even = even.

$2(even)+2(even)=4(even)$ .

An even number plus another even number is an even number because 2 plus 2 equals 4 and 4 is an even number