What is the final digit of 1 1 × 3 3 × 5 5 × 7 7 × ⋯ × 2 0 1 5 2 0 1 5 ?
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Eloquent indeed.
Thought of the ans in the same way.
can u solve the question kindly? :)
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Factoring out a 5, we see that the given number is 5 times an odd number, of the form 5 ( 2 n + 1 ) . Now 5 ( 2 n + 1 ) = 1 0 n + 5 has the last digit 0 + 5 = 5 .
It is known ;)
Yeah We have same thinking.
There is a 5 in the multiplications so last digit 0 or 5.
There is no even number so the last digit is odd so it is 5.
No thought needed, 5 was involved and 0 wasn't an option thus only answer could be 5... took 2 seconds to answer with no math used.
since the product contain 5
Didn't have even number in the question, just odd number can divided for 5. Easy to know consecutive even numbers can divide for 5 and have final digit is 5. So the answer is 5
odd number * 5 = 5
Correct Logic.
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Last Digit = ( 2 0 0 0 + 1 5 ) 2 0 1 5 → L a s t D i g i t i s 5 followed by 2000 zeros
ins't (2000+15 =2015) or have i done it wrong all my life!
look at the solution you posted mate.! then look at my previous comment. i think i can expect that you can understand it yourself!
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An odd multiple of 5 ends in a 5