Odd Proper Divisors
Probability
Level
pending
The Number of odd proper divisors of is :
(p+m+n+1)(n+1) -1
(p+1)(m+1)(n+1) -1
(p+m+n+1)(n+1)-2
(p+m)(m+1)(n+1)-2
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1 solution
3 p ⋅ 6 m ⋅ 2 1 n = 2 m ⋅ 3 ( p + m + n ) ⋅ 7 n Therefore , the required number of proper divisors = numbrer of selections of any number of 3s and 7s [since, for odd divisors 2 must not be selected ] therefore after selection , ( p + m + n + 1 ) ( n + 1 ) − 1