Odds and squares
Algebra
Level
1
The sum of four consecutive odd integers equals the area of a square whose perimeter is 32. What is the largest of the four integers?
15
13
19
17
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1 solution
Moderator note:
Simple standard approach.
A square whose perimeter is 32 has a side length of 8, hence an area of 8 * 8 = 64.
64/4 = 16, so the integers are symmetric around 16. Since they are consecutive, the middle two must be 15 and 17. That makes the two flankers 13 and 19.
The largest of those numbers is 19.