Of-course not by me!!
Number Theory
Level
1
The sum of the digits of a 3 digit number is subtracted from the number. The resulting number is always divisible by
5
11
9
6
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1 solution
Let the 3 digit no. be 100a + 10b + c. Then sum of digits = a+b+c so, (100a+10b+c) - (a+b+c) = 99a + 9b = 9 ( 1 1 a + b ) So it is divisible by 9.