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Classical Mechanics Level 2

An astronaut on a space walk in deep intergalactic space takes two lead spheres and places them in space, exactly $2\text{ m}$ apart. One lead sphere has a mass of $6\text{ kg}$ and the other a mass of $10\text{ kg}$ . What is the gravitational attraction between the spheres in Newtons?

For purposes of this calculation, assume a value for $G$ of $\dfrac{20}3 \times 10^{-11} \text{ N m}^{2}\text{/kg}^{2}$ .

The answer is 1E-9.

1 solution

Denton Young
Jun 8, 2016

G = 20/3 * $10^{-11}$ , masses are 6 and 10, d = 2. So we get (6 * 10) / (4) * G = 15 * G = (300/3) * $10^{-11}$ = $10^{-9}$

Moderator note:

Simple standard approach.

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The answer is 1E-9.

1 solution

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