Oh, Gcd!

a , b a, b are positve integers such that gcd ( a , b ) = 1 \gcd(a,b) = 1 . For any natural m m , given n = a + b m n = a + bm ,

Evaluate gcd ( a b + b m , a b + b n ) \gcd (a-b+bm, a-b+bn) .


The answer is 1.

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1 solution

Rama Devi
Aug 7, 2015

Better to give it in multiple choice.

So... How do you solve this?

Rico Lee - 4 years, 7 months ago

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