Oh Gravity!!

$We\quad know\quad that\quad { F }_{ Gravi. }=\frac { G{ m }_{ 1 }{ m }_{ 2 } }{ { r }^{ 2 } } \\ By\quad increasing\quad { m }_{ 1 }\quad and\quad { m }_{ 2 }\quad by\quad a\quad factor\quad of\quad 1/2\\ The\quad new\quad masses\quad are\quad { M }_{ 1 }\quad and\quad { M }_{ 2 }\\ { M }_{ 1 }\quad =\quad { m }_{ 1 }\quad +\quad 1/2\quad { m }_{ 1 }\quad =\quad \frac { 3 }{ 2 } { m }_{ 1 }\\ { M }_{ 2 }\quad =\quad \frac { 3 }{ 2 } { m }_{ 2 }\\ { { F }^{ ' } }_{ Gravi. }=\frac { 9 }{ 4 } \frac { G{ m }_{ 1 }{ m }_{ 2 } }{ { r }^{ 2 } } \\ So,\quad Total\quad change\quad in\quad force\quad =\quad \frac { { { F }^{ ' } }_{ Gravi. }-{ { F } }_{ Gravi. } }{ { { F } }_{ Gravi. } } \times 100\\ =\quad \frac { \frac { 9 }{ 4 } \frac { G{ m }_{ 1 }{ m }_{ 2 } }{ { r }^{ 2 } } -\frac { G{ m }_{ 1 }{ m }_{ 2 } }{ { r }^{ 2 } } }{ \frac { G{ m }_{ 1 }{ m }_{ 2 } }{ { r }^{ 2 } } } \times 100\\ =\quad \frac { 5 }{ 4 } \times 100\quad =\quad 125\quad percent$

CHEERS!!:)

$\text{With original masses, } F_G\ = \dfrac{GmM}{r^2}$

$\text{After increasing the mass, } F_G\ = \dfrac{GmM\times{150^2}}{100^2r^2}$

$\text{Percentage increase}\ =\ \dfrac{\dfrac{GmM\times{150^2}}{100^2r^2}}{\dfrac{GmM}{100r^2}}-100 = 225-100 = 125\%$