Find the coefficient of in the expansion of
Assume all constants are equal to
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Taking a look at the first few terms in the sequence, we find this. ∫ ∫ d t d t = ∫ t + C d t = 2 1 t 2 + C t + D ∫ ∫ ∫ d t d t d t = ∫ ∫ t + C d t d t = ∫ 2 1 t 2 + C t + D d t = 6 1 t 3 + 2 C t 2 + D t + F . It appears that the coefficient of the n th term in the sequence is equal to a constant times the reciprocal of n ! In fact, the n th term in the sequence is equal to this. n ! t n + i = 1 ∑ n − 1 i ! C i t i Because all constants are equal to 1 , the t n term is equal to n ! t n with a coefficient of n ! 1 .