Ohms law failed?

Due to the distributive nature of the circuit elements the ohms law fails, as ohms law treat the elements as lumped(that can be treated as point form), but at high frequency the distributive nature becomes dominant, and the conductor start acting as waveguide instead of treating it as a simple conductor.

Ohms law state that V=IR and at high frequencies this is wrong . Because any circuit in practical circumstances(don't use this about or near zero kelvin because then we can't even use classical electrodynamics and have to use quantum electrodynamics) have some finite capacitance and inductance (theoritical it can be zero ) and so we need to solve a second order differential equation instead of a approximate equation of ohms law. The equation tell us that potential drop across some circuit is some constant times charge plus some constant times current ( time derivative of charge) plus some constant times rate of change of current.

If we us q for charge and q* represent time derivative of q, then mathematically our equation is ξ=(q/c)+(rq )+(lq *)( here r= resistance. c=capacitance, l=inductance)

Now we solve this equation for a normal case where q and ξ(potential drop) are sinusoidal functions of time then we can see that at moderate frequency ohm law is nice but at high frequency it breaks down.