An algebra problem by Nazmus sakib

Algebra Level 2

5 years ago, the average age of Fahim and Arif was 15.
The average age of Fahim, Arif, and Sahariar today is 20.

How old will Sahariar be after 10 years?

30 40 45 35

Nazmus Sakib by Nazmus sakib , 24, Bangladesh

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2 solutions

F F = age of Fahim today

A A = age of Arif today

S S = Sahariar today

Five years ago

( F − 5 ) + ( A − 5 ) 2 = 15 \frac{(F-5) + (A-5)}{2} = 15

F − 5 + A − 5 = 30 F - 5 + A - 5 = 30

F + A = 40 F + A = 40 (equation 1)

Today

F + A + S 3 = 20 \frac{F + A + S}{3} = 20

F + A + S = 60 F + A + S = 60

substitute equation 1 to the above equation, we get

40 + S = 60 40 + S = 60

S = 20 S = 20

10 Years form now

S = 20 + 10 = 30 S = 20 + 10 = 30

2 Helpful 0 Interesting 0 Brilliant 0 Confused
谦艺 伍
Apr 9, 2017

Notice that the average age of Fahim and Arif is 15 + 5 = 20 today.

Since the average age of Fahim, Arif, and Sahariar today is also 20, Sahariar is also 20 today.

So, Sahariar will be 30 after 10 years.

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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