On the third day of Christmas, Calvin gave to me

As a simple rule, just remember any word with $n$ distinct letters can be rearranged in $n!$ ways.

Here "Poules" have all distinct characters, so the number of rearrangements are equal to $6! = 720$ .

If, consider the situation where the letters are repeated. Suppose, we have "Popoulleso". Here, the number of rearrangements would be $\frac{10!}{2! \times 3! \times 2!}$ . The denominator terms refer to the number of repetitions of each letters - 'p' and 'l' are repeated twice and 'o' is repeated thrice. Ofcourse, that wouldn't help in this question. I just wrote it as a side note for someone who doesn't confuse it with a word having repeated letters.

There are 6 ways for the first, 5 for the second, .... and 1 for the last. 6!=720.

there are 6 letters . so to rearrange them there are 6! ways = 6x5x4x3x2x1= 720 there fore 720 ways to rearrange " Poules "

There are 6 letters in the word 'poules'. Hence to there are 6! = 720 different ways of arranging the letters.

6! = 720

"Poules" have 6 letters, so all the posible ways that the word can be rearranged are 6! = 720.

It's simple The fact of the answer is 6! 6×5×4×3×2×1 = 720

It is quite simple.Always the ways of rearrangement of letters in a word is the facorial of number of letters in the word.Hence,here it is number of letters is 6.So the factorial of 6 is 720.Thus the letters of the word could be rearranged in 720 ways.

6 ! = 720 solutions.

POULES have 6 distinct characters . so total no. of rearrangements are 6! = 720 . as each character can be used only once.

There are 6 unique letters in the word POULES which can be arranged in 6 ! ways = 720.

since the word "poules"consist of 6 letters and no letter is repeated so different number of ways is 6! = 6 5 4 3 2*1 = 720

7!

There are $6$ different letters in the word 'Poules', hence the number of ways to rearrange the letters is $6! = \boxed{720}$ .

since there are no repeats allowed the largest amount of combinations is 6!, or 720

Simple; take out the factorial of 6, which is the number of letters in the word. Factorial of 6 = 6 x 5 x 4 x 3 x 2 x 1 = 720

Number of letters (alphabets) in the word $'Poules'$ are $7$ , therefore the number of possible combinations are $7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = \boxed{720}$

In the word 'Poules', there are 6 distinct letters and these letters can be rearranged by permuting the 6 letters taken all at a time. So, the letters can be rearranged in $=6P6 = 6! = \boxed{720}$ ways.

So, total no. of ways(rearrangements for the word) $=\boxed{720}$

Very simply, a way to find how many ways to arrange n objects is n!, or n factorial. 6! is 6 * 5 * 4 * 3 * 2 * 1 = 720. Therefore: You can arrange the 6 letters in poules in 720 ways. This amazing numberphile video includes a bit more about factorials, particularly 0! http://www.numberphile.com/videos/zero_factorial.html

There are 6 alphabets in the word Poules so, 6! = 6 5 4 3 2*1 =720

POULES has 6 words so there are 6 factorial ways to rearrange this word so 6 5 4 3 2*1=720 ways

ther are 6 letters in "poules" , s0 ways of arrangment= 6!= 720

There's 6 alphabet and no alphabet is repeated. So, it's 6!

Number of ways of rearranging a "n" letter word which has no repeated letter=n! Hence, number of ways of arranging poules(6-letters) = 6! = 720

6! = 6 x 5 x 4 x 3 x 2 x 1 = 720

Since there are six distinct letters in "POULES",

the total number of ways to rearrange them is $6!$