One

Algebra Level 1

Find x x given that y = 2 y=2 and 0 ! 1 + 1 0 = 4 x y 0! \cdot 1 + 1^0 =4xy .

0.5 2 1 0.25

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3 solutions

Hung Woei Neoh
Aug 3, 2016

0 ! × 1 + 1 0 = 4 x y 1 × 1 + 1 = 4 x ( 2 ) 1 + 1 = 8 x 8 x = 2 x = 2 8 = 0.25 0! \times 1+ 1^0 = 4xy\\ 1 \times 1 + 1 = 4x(2)\\ 1+1=8x\\ 8x=2\\ x=\dfrac{2}{8} = \boxed{0.25}

0! Means what

ankit raj - 4 years, 10 months ago
Md Zuhair
Aug 3, 2016

Here 1 0 + 0 ! = 1 + 1 = 2 1^0 + 0! = 1+1 = 2 and then acc to the problem 2 = 4 x y 2= 4xy hence x y = 0.5 xy = 0.5 now y = 2. y=2 . Hence x = 1 / 4 = 0.25 x = 1/4 = 0.25 . That is our ans

Felipe Knöller
Aug 2, 2016

0 ! = 1 , 1 0 = 1 0! = 1, 1^0 = 1 So, we have: 0 ! 1 + 1 0 = 4 2 x 1 + 1 = 8 x x = 2 / 8 = 1 / 4 = 0.25 0!*1 + 1^0 = 4*2x\\ 1 + 1 = 8x\\ x = 2/8 = 1/4 = 0.25

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