One

Algebra Level 1

Find $x$ given that $y=2$ and $0! \cdot 1 + 1^0 =4xy$ .

0.5 2 1 0.25

3 solutions

Hung Woei Neoh
Aug 3, 2016

$0! \times 1+ 1^0 = 4xy\\ 1 \times 1 + 1 = 4x(2)\\ 1+1=8x\\ 8x=2\\ x=\dfrac{2}{8} = \boxed{0.25}$

0! Means what

ankit raj - 4 years, 10 months ago

Md Zuhair
Aug 3, 2016

Here $1^0 + 0! = 1+1 = 2$ and then acc to the problem $2= 4xy$ hence $xy = 0.5$ now $y=2 .$ Hence $x = 1/4 = 0.25$ . That is our ans

Felipe Knöller
Aug 2, 2016

$0! = 1, 1^0 = 1$ So, we have: $0!*1 + 1^0 = 4*2x\\ 1 + 1 = 8x\\ x = 2/8 = 1/4 = 0.25$