One dimensional motion!

Classical Mechanics Level 3

From a town, cars start at regular intervals of 30 s and run towards a second town with a constant speed of 60 km/hr so that the time between their arrival is Δ t 1 \Delta t_1 . At some point of time, all of the cars leaving the first town reduce their speed to 40 km/hr due to bad weather conditions. What will be the time interval between consecutive cars reaching the second town after slowing down?

45s 20s 40s 30s

Ťånåy Nårshånå by Ťånåy Nårshånå , 24, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Remembering the basic formula: d i s t a n c e = v e l o c i t y × t i m e distance = velocity \times time

And knowing that the distance stays the same, we get: v e l o c i t y 1 × t i m e 1 = v e l o c i t y 2 × t i m e 2 velocity_{1} \times time_{1} = velocity_{2} \times time_{2} t i m e 2 = ( v e l o c i t y 1 × t i m e 1 ) / v e l o c i t y 2 time_{2} = (velocity_{1} \times time_{1} ) / velocity_{2} t i m e 2 = ( 60 k m / h r × 30 s ) / ( 40 k m / h r ) time_{2} = (60 km/hr \times 30 s) / (40 km/hr) t i m e 2 = 45 s time_{2} = \boxed{45 s}

6 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...