One is "some others"

Calculus Level 3

Let f ( x ) f(x) be a quadratic equation which is positive for all real x x . If g ( x ) = f ( x ) + f ( x ) + f ( x ) g(x) = f(x) + f'(x) + f''(x) for all real x x , what is g ( x ) g(x) ?

Clarification: f ( x ) f'(x) is the derivative of f ( x ) f(x) and f ( x ) f''(x) is the derivative of f ( x ) f'(x) .

Non-negative Non-positive Postive Negative

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Tom Engelsman
Dec 29, 2018

Let f ( x ) = A x 2 + B f(x) = Ax^2 + B with A , B R + . A,B \in \mathbb{R^{+}}. The first and second derivatives compute to: f ( x ) = 2 A x , f ( x ) = 2 A . f'(x) = 2Ax, f''(x) = 2A. The sum g ( x ) = f ( x ) + f ( x ) + f ( x ) g(x) = f(x) + f'(x) + f''(x) evaluates to:

g ( x ) = ( A x 2 + B ) + ( 2 A x + 2 A ) = A ( x 2 + 2 x + 1 ) + ( A + B ) = A ( x + 1 ) 2 + ( A + B ) g(x) = (Ax^2 + B) + (2Ax + 2A) = A(x^2 + 2x + 1) + (A + B) = A(x+1)^2 + (A+B)

The minimum value of g ( x ) g(x) over all reals is A + B > 0 A+B > 0 ; hence, it is a positive-valued function.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...