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Algebra Level 5

20 x + 16 y + 2016 x + 4028 y \large 20x+16y+\dfrac{2016}{x}+\dfrac{4028}{y}

Given that x x and y y are positive real numbers satisfying x + y 2016 x+y\geq 2016 , find the minimum value of the expression above.

Round your answer to the nearest integer.


Inspiration .


The answer is 32438.

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