A classical mechanics problem by Ashish Menon

Classical Mechanics Level 3

A body of mass m m placed on a horizontal frictionless table moves forward with a constant velocity v v for t t seconds. What is the net force acting on the body till t t seconds?

Take g g as the acceleration due to gravity.

m g mg m ( v + g ) t \dfrac{m(v + g)}{t} Zero m v t \dfrac{mv}{t}

Ashish Menon by Ashish Menon , 20, India

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2 solutions

Ashish Menon
Jul 29, 2016

The body moves with a constant velocity which means that the acceleration (rate of change of velocity) = 0, thus F = m a = m × 0 = Zero F = ma = m×0 = \color{#3D99F6}{\boxed{\text{Zero}}}

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A nice tricky question , it will be better to highlight the word * Net * in the question

Sabhrant Sachan - 4 years, 10 months ago
Sargam Yadav
Jul 30, 2016

The body moves with constant velocity in horizontal direction.... so, no force acts on it in horizontal direction..... as the downward vertical force acting on the body .i.e mg is balanced by normal(vertical ) force which is equal and opposite to mg , NO NET FORCE acts on the body .i.e NET FORCE acting on the body is ZERO..

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