One small mistake and lo behold

Take a look at the thin rod(of length a a ) above.

The mass density along the rod varies as σ = σ 0 ( 1 + x n a n ) \sigma=\sigma_{0}(1+\frac{x^{n}}{a^{n}}) where n n is a positive integer.

While calculating the co-ordinates of the centre of mass of the rod, we assume(wrongly) the COM to be at the geometric centre ie., ( a 2 , 0 ) (\frac{a}{2},0)

Now, we know that's wrong and find the actual co-ordinate.

We note that the actual x x co-ordinate is a 2 + δ X \frac{a}{2}+\delta X where X X is the actual co-ordinate of the COM.

Define 100 δ X X 100\frac{\delta X}{X} as percentage error

Approximately what mean maximum percentage error will we have made in assigning the COM to rods from n = 1 n=1 to n = 20 n=20 ie., 100 20 n = 1 n = 20 δ X n X n \displaystyle \frac{100}{20} \sum_{n=1}^{n=20} \frac{\delta X_{n}}{X_{n}} where X n X_{n} is the COM when n n is the exponent of x x in the surface density expression

You may use the approximations 1 + 1 2 + + 1 21 3.645 1 + \dfrac12 + \cdots + \dfrac1{21} \approx 3.645 and 1 23 + 1 24 + 1 25 0.12514 \dfrac1{23} + \dfrac1{24} + \dfrac1{25} \approx 0.12514 .

Give your answer to the nearest integer.


If you are looking for more such simple but twisted questions, Twisted problems for JEE aspirants is for you!
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