One theorem to rule them all... do you know what it is?

Geometry Level 3

ABC is a triangle where AC is of length 13, and AB is of length 15. Point D is constructed on side CB such that the ratio C D : D B = 1 2 CD:DB=\frac{1}{2} . Let the cevian AD be of length 6. If CD can be expressed as a 6 \frac{\sqrt{a}}{\sqrt{6}} , find a a .


The answer is 455.

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5 solutions

Finn Hulse
Mar 12, 2014

The "One Theorem to Rule Them All" is Stewart's Theorem. It is a relatively complex formula that is really nifty to hold on to. By letting CD be x x , and DB be 2 x 2x , plugging that into the formula produces x 2 = 455 6 x^{2}=\frac{455}{6} . Thus a = 455 a=455 . It's a really nifty theorem that I have seen on tons of AIME problems. :D

I used the cosines rule :p :p

Eddie The Head - 7 years, 2 months ago

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Not a bad approach, considering that's what Stewart's Theorem is based on. :D

Finn Hulse - 7 years, 2 months ago

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Yeah, Stewart's theorem is derived from Cosine Rules. Solving using Cosine Rules is a more original approach to the problem.

Venkata Karthik Bandaru - 6 years, 3 months ago

Stewarts theorem

Mardokay Mosazghi - 7 years ago
Piyush Khushlani
Mar 11, 2014

Let the ratio be x:2x Then we all have to do is put cosine law for theta and pie-theta.. Add the equations to become zero and then find the value of x.. It comes x^2 = 455/6

You can use The Stewart's Theorem

Perfect.

Finn Hulse - 7 years, 3 months ago
Ahmad Saad
Nov 13, 2016

Nam No
May 28, 2014

draw altitude AH;let CH=m , CD=x; use Pythagorean theorem: A D 2 AD^{2} = A H 2 AH^{2} + H D 2 HD^{2} ; A C 2 AC^{2} = A H 2 AH^{2} + C H 2 CH^{2} ; =>(AC-AD)(AC+AD)=(CH-HD)(CH+HD) ; =>133=(2m-x)x=>133=2mx- x 2 x^{2} =>399=6mx-3 x 2 x^{2} (1 ) ; do the same thing with AC and AB =>56=(3x-2m)3x=>56=9 x 2 x^{2} -6mx (2 ) ; plus (1 ) with (2 ) =>455=6 x 2 x^{2} => x 2 x^{2} =455/6 .

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