ABC is a triangle where AC is of length 13, and AB is of length 15. Point D is constructed on side CB such that the ratio C D : D B = 2 1 . Let the cevian AD be of length 6. If CD can be expressed as 6 a , find a .
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I used the cosines rule :p :p
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Not a bad approach, considering that's what Stewart's Theorem is based on. :D
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Yeah, Stewart's theorem is derived from Cosine Rules. Solving using Cosine Rules is a more original approach to the problem.
Stewarts theorem
Let the ratio be x:2x Then we all have to do is put cosine law for theta and pie-theta.. Add the equations to become zero and then find the value of x.. It comes x^2 = 455/6
You can use The Stewart's Theorem
Perfect.
draw altitude AH;let CH=m , CD=x; use Pythagorean theorem: A D 2 = A H 2 + H D 2 ; A C 2 = A H 2 + C H 2 ; =>(AC-AD)(AC+AD)=(CH-HD)(CH+HD) ; =>133=(2m-x)x=>133=2mx- x 2 =>399=6mx-3 x 2 (1 ) ; do the same thing with AC and AB =>56=(3x-2m)3x=>56=9 x 2 -6mx (2 ) ; plus (1 ) with (2 ) =>455=6 x 2 => x 2 =455/6 .
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The "One Theorem to Rule Them All" is Stewart's Theorem. It is a relatively complex formula that is really nifty to hold on to. By letting CD be x , and DB be 2 x , plugging that into the formula produces x 2 = 6 4 5 5 . Thus a = 4 5 5 . It's a really nifty theorem that I have seen on tons of AIME problems. :D