Exponentials Vs. Polynomials In A Limit

Calculus Level 1

lim x 0 3 x 2 x x \large \lim_{x\to0} \dfrac{3^x-2^x} x

If the value of the limit above can be expressed as ln ( a b ) \ln \left( \dfrac ab\right) , where a a and b b are coprime positive integers, find a + b a+b .


The answer is 5.

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2 solutions

Rishabh Jain
Mar 1, 2016

Apply (1). L'hopital Rule or (2).Use lim x 0 a x 1 x = ln a \color{#D61F06}{\text{(2).Use }\lim_{x\to 0}\dfrac{a^x-1}{x}=\ln a} Given limit can be written as: L = lim x 0 3 x 1 x lim x 0 2 x 1 x \large\mathfrak{L}= \lim_{x\to0} \dfrac{3^x-1} x- \lim_{x\to0} \dfrac{2^x-1} x = ln 3 ln 2 = ln ( 3 2 ) \large =\ln 3- \ln 2=\ln(\dfrac 32) 2 + 3 = 5 \huge \therefore ~ 2+3=\boxed{\color{#007fff}{5}}

Sandeep Bhardwaj
Mar 1, 2016

HINT: Use L'hopital's Rule to solve the given limits .

You are absolutely right

Adarsh Mahor - 5 years, 3 months ago

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