Only Oxidation

Chemistry Level 1

Find modulus of oxidation state of oxygen in the compound, H X 2 O X 2 \ce{ H_{2}O_{2}} .


The answer is 1.

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1 solution

Adarsh Mahor
Mar 15, 2016

Its simple just use Oxidation state of H y d r o g e n = 1 \ce{Hydrogen}=1 H X 2 O X 2 = 0 ( 1 ) 2 + 2 O = 0 thus O = 1 \therefore \ce{H2O2}=0\\ (1)2+2\ce O= 0\\ \text{thus}\quad \ce O =1

Hydrogen can't have an O.S. of -1.

All group 1 elements have O.S. of (+1) in their compounds.

Pulkit Gupta - 5 years, 3 months ago

There are clear laws for easier non living compounds: H +1 (I), O -2 (-II) metals are most of the time positive elements are neutral

i am apolgizing for my bad english! The last sentence is tricky!! if you dont understand imagine it without him

Trash of Bros - 3 years, 5 months ago

Wait, you asked for the oxidation state of hydrogen and you are finding the oxidation state of oxygen. What is this?

Sravanth C. - 5 years, 3 months ago

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Sorry it's just by an simple mistake

And thanks for spotting my mistake

Adarsh Mahor - 5 years, 2 months ago

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Never mind! BTW, I've edited your solution too, hope it looks good now! ¨ \ddot\smile

Sravanth C. - 5 years, 2 months ago

Yeah, that's a wrong thing you've done there, though both the question and the answer are correct, your solution is flawed. Please read this wiki: oxidation number .

Sravanth C. - 5 years, 3 months ago

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