Oof

We are asked to calculate $f'(2)$ , when $f(x)=\frac{g(x)}{x}$ where $g(2) = 4$ and $g'(20=8$ . To do this, we can use the quotient rule to compute $f'(x)=\frac{g'(x) \times x-g(x) \times 1}{x^2}$ $\Rightarrow f'(2)=\frac{8 \times 2 - 4 \times 1}{2^2}$ $\Rightarrow f'(2)=\frac{16-4}{4}$ $\Rightarrow \boxed{f'(2)=3}$