x + 1 − x − 1 − 2 − x − 2 ( x 2 + 2 ) 6 x 2 − 2 ( x + 1 ) x 2 − 1 + 3 x − 6 ≤ 0
Find the interval of x that satisfy the inequality above.
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The values for x when the statement is less than 0 (negative) are bound by the square roots of 2-x and x-1 from the denominator. When x is less than 1, the value of the expression is no longer a real number. This is also true when x > 2. This limits the possible outcomes to values between 1 and 2 inclusive.
Within that range of values, the numerator will always be positive, and the denominator will always be negative so the resulting expression will always be negative.