Ooh! This looks complicated, but is it really complicated?

Algebra Level 3

6 x 2 2 ( x + 1 ) x 2 1 + 3 x 6 x + 1 x 1 2 x 2 ( x 2 + 2 ) 0 \dfrac{6x^2 - 2(x+1) \sqrt{x^2-1} + 3x-6}{x+1 -\sqrt{x-1} - \sqrt{2-x} - \sqrt{2(x^2+2)}} \leq 0

Find the interval of x x that satisfy the inequality above.

1 x 5 4 1 \leq x \leq \frac {5}{4} 1 x 2 1 \leq x \leq 2 x 5 4 x \leq \frac {5}{4} x 0 x \geq 0

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1 solution

Dan Brabec
Apr 15, 2021

The values for x when the statement is less than 0 (negative) are bound by the square roots of 2-x and x-1 from the denominator. When x is less than 1, the value of the expression is no longer a real number. This is also true when x > 2. This limits the possible outcomes to values between 1 and 2 inclusive.

Within that range of values, the numerator will always be positive, and the denominator will always be negative so the resulting expression will always be negative.

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