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simple apply Dmas rule
Simply the multiplication process is first binary process order x or / first then +or_
PEMDAS
according to BODMAS RULE B- Brackets first O- Orders (i.e- Powers and Square Roots, etc.) DM- {Division and Multiplication (left-to-right)} AS- {Addition and Subtraction (left-to-right)}
{(1x2)+(3x4)+(5x6)+(7x8)}/10 =(2+12+30+56)/10 =100/10 =10
1*2=2
3*4=12
5*6=30
7*8=56
(2+12+30+56)=100
100/10=10
(1 x 2 + 3 x 2 x (1 x 2) + 5 x 3 x (1 x 2) + 7 x 4 x (1 x 2)) / 10 = (1 x 2) x (1 + 3 x 2 + 5 x 3 + 7 x 4) / 10 = (1 x 2) ( 1 + 7 x 3 +7 x 4) /10 = (1 x 2) ( 1 + 7 x 7) /10 = 10
Apply the PEMDAS (Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction) Rule in this example.
First, you need to look at this long parenthesis.
(1 x 2 + 3 x 4 + 5 x 6 + 7 x 8)
Try to mind the numbers between the multiplication symbols (factors). Then multiply all the numbers.
You should come up with this... (2 + 12 + 30 + 56) / 10
Then add up the remaining numbers in the parenthesis "()" and divide that number by ten.
The final answer is 10.
You have to use the BODMAS rule to correctly find out the answer.
( 1 × 2 + 3 × 4 + 5 × 6 + 7 × 8 ) ÷ 1 0 = ( 2 + 1 2 + 3 0 + 5 6 ) ÷ 1 0 = 1 0 0 ÷ 1 0 = 1 0
1 × 2 + 3 × 4 + 5 × 6 + 7 × 8 = 2 + 12 + 30 + 54 = 1 0 0
1 0 1 0 0 = 1 0
frnds use BODMAS rule.............. 1st step:- multiply the digits which are in the bracket.. 2nd step:- add the digits and you will get a sum of 100... final step:- divide 100 by 10 and you will get 10...........................THANK U
(2+12+30+56)/10 = (100) /10 = 10
PEMDAS [(1 2)+(3 4)+(5 6)+(7 8)]/10 (2+12+30+56)/10 100/10 10
1 2=2 ; 3 4=12 ; 5 6=30 ; 7 8=56 2+12+30+56=100 100/10=10
simply multiply and add nmbers as the signs are given rspectivly and after solving bracket (always sovle bracket first) and then divide answer obtained by solving bracket with 10 and you will get the answer...!
{2+12+30+56}\10 = 100\10 = 10
=(1x2) + (3x4) + (5x6) + (7x8) ÷ 10
= 2 + 12 + 30 + 56 ÷ 10
= 14 + 86 ÷ 10
= 100 ÷ 10
Answer : 10
good
By Rule of BADMAS
first we open a Bracket so we do multiply and after Multyply we do Additon and after open the Bracket last step is Divide.
=(2+12+30+56)/10 =100/10 =10 Ans.
first of all you multiply the number then add them all together then divided by 10, 100/10 the answer is 10
Answer = [(1 2)+(3 4)+(5 6)+(7 8)]/10 =[2+12+30+56]/10 =100/10 =10
(1 x 2 + 3 x 4 + 5 x 6 + 7 x 8)/10 = (2 + 12 + 30 + 56)/10 = 100/10 = 10
According to BODMAS we will solve the operation of Multiplication and then all the products will be added because they are enclosed with round bracket and will be divided by 10 afterwards. (Note: When mutiple opeartions are to be performed in single enclosed bracket we will solve them according to the rule of BODMAS i.e (Bracket Of Division Multiplication Addition Subtraction) "Operations are to be performed inthis particular order for correct answer" Keep this in mind before leaping for solution.)
Mathematical Solution : (How I solved it) Q: (1x2+3x4+5x6+7x8)/10 sol: = (2+12+30+56)/10 =(100)/10 =10 Ans. Quite simple :)
STEP1: ((1 2)+(3 4)+(5 6)+(7 8))/10 STEP2: (2+12+30+56)/10 STEP3: 100/10
we must solve what's between arcs Firstly ! We must multiply first So, 1 × 2 = 2 then we have now 2+3×4+5×6+7×8 between the two arcs
>> 2+12+5×6+7×8 ... it's gonna to be >> 2+12+30+7×8.... it's gonna to be >>2+12+30+56.... it's gonna to be >> = 100 /10..... then we have now = 10 :)....
(1x2+3x4+5x6+7x8):10= (1x2)+(3x4)+(5x6)+(7x8):10 = 100:10=10
((1x2)+(3x4)+(5x6)+(7x8)) / 10 = 10
[(1x2)+(3x4)+(5x6)+(7x8)]/10
first of all we will multiply the consective numbers and then add with the next multiplied numbers and after completing process under the bricket we will divide it on 10
1x2=2 3x4=12 5x6=30 7x8=56 So 1x2+3x4+5x6+7x8=100 Therefore (1x2+3x4+5x6+7x8)/10=100/10=10
Easy folks All you need to remember while doing this question is the rule of BODMAS so first multiply then add then divide 1X2= 2 + 3 X 4 = 12 + 5 X 6 = 30 + 7 X 8 = 56 SO you will come up with 2 + 12 + 30 + 56 = 100 and then 100/10 = 10 therefore the answer is 10
1 2=2 3 4=12 5 6=30 7 8=56 (2+12+30+56)/100=10
BIDMAS [(1 2)+(3 4)+(5 6)+ (7 8)]/10 (2+12+30+56)/10 (14+86)/10 = 100/10=10 ANS.10
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(1x2+3x4+5x6+7x8)/10 =(2+12+30+56)/10 =100/10 =10