A particle of mass travels along a one-dimensional path from to . Here, and represent space and time coordinates. From to , the particle has constant velocity , and from to , the particle has constant velocity .
Define the quantity as follows:
The quantity is a function of variables and . Subject to the constraint , determine the values of and such that the following is true.
What is the relationship between the resulting and values.
Note: To get the most out of this problem, solve it on its own terms without applying any Newtonian intuition. What is the physical significance of this result?
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We are asked to minimize the convex function:
S = 2 m T ( v 1 2 + v 2 2 )
Subject to:
v 1 + v 2 = T D
Introducing a Lagrange multiplier and augmenting the cost function: F = S + λ ( v 1 + v 2 − T D )
Now:
∂ v 1 ∂ F = m T v 1 + λ = 0 ∂ v 2 ∂ F = m T v 2 + λ = 0
Solving for v 1 and v 2 in terms of λ leads to the conclusion that:
v 1 = v 2
Now, coming to the physics of this problem. The quantity S can be thought of as the action integral - The time integral of the Lagrangian:
S = ∫ 0 2 T ( T − V ) d t
In the absence of any external forces or potentials, the action integral becomes:
S = ∫ 0 2 T ( T ) d t S = ∫ 0 T 2 m v 1 2 d t + ∫ T 2 T 2 m v 2 2 d t S = 2 m T ( v 1 2 + v 2 2 )
So essentially, according to the problem statement, at time t = T , there is an abrupt change in the speed of the particle. From the laws of motion, we know that this is an impossibility in the absence of a force or potential energy that tends to drive the particle. Therefore, our intuition tells us that the speed must not change at any instant. This is in agreement with the result of the optimization problem.
Another very neat observation that we see from the optimization problem is that the particle's linear momentum is always constant, which is also in agreement with classical intuition that momentum is conserved in the absence of external forces.