Consider as a left -module (Where addition and scalar multiplication are as usual when considering as a ring and as a subring of ). Does span ?
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No.
Any linear combination of reciprocals of odd primes will have the form b a for some a , b ∈ Z where b = 0 is odd. So any linear combination of reciprocals of primes will have the form 2 c + b a = 2 b b c + 2 a which cannot be equal to 4 1 . So 4 1 is not in the span of { p 1 ∣ p prime }