If the number of lemons become the double of oranges, the number of fruits after the marketer sell one basket should become multiple by 3.

The total of fruits are 73 ( see the image), and the only basket that he can sells to get a multiple by 3 is the basket with 13 fruits. The number of fruits becomes 60.

Answer : 13

Hello,

as the total number of fruits in the 5 baskets = 8 + 11 + 13 + 18 + 23 = 73

and let le = lemons , or = oranges,

stated that le : or = 2 : 1,

le / or = 2 / 1(if 1 one the box is taken out),

le = 2or(1st)

as we know that le + or = 73,

so try to take out each box that is consist of (8,11,13,18,23),

as you can get the answer from the box that is consist of 13 fruits,

le + or = 73 - 13 =60(2nd),

substitute (1st) into (2nd),

2or + or = 60

3or =60

or = 60 / 3 = 20

le = 60 - 20 = 40,

as to get the truth whether the number of le is twice as of that or if that box(consist of 13 fruits is taken out),

by comparison,

le / or = 40 / 20

le / or = 2 / 1

le = 2or(proven there),

thanks....

Lets say that we have x oranges when we have already sold the basket. Since the number of lemons will be the double of oranges, we will have 2x lemons. So if we add them, we get a total of 3x fruits, which is an integer divisible by 3. This means that when the basket has already been sold, we will have a number of fruits divisible by 3.

Then, we add the total of fruits and we get 73, which is congruent to 1 modulo 3, which tells us that we must quit a basket that has a number of fruits congruent to 1 modulo 3, to get a number divisible by 3. We check each basket and we see that 8 is congruent to 2 modulo 3, 11 is congruent to 2 modulo 3, 13 is congruent to 1 modulo 3 , 18 is congruent to 0 modulo 3 and 23 is congruent to 2 modulo 3.

Therefore, the only number we can take is 13.

if there are double lemons of no of oranges means the quantity left is divisible by 3..so when we remove bag of 13 then left quantity is 60 which is divisible by 3..but when we sell any of other bag then the left quantity is not divisible by 3.. thats all!!

same way with Brazilian.

Let,the no.of oranges is x

Then certainly the no. of lemon is 2x

So the no. of total fruits after selling one busket [P] is=x+2x=3x{the multiple of 3}

Surely, 13 is the only option which fulfill this condition.[as 63-13=60 is divisible by 3]

The sum of 4 of the baskets must by dividable by 3 .. The 23 basket isn't in the choices Then we will add 4 baskets to each others " the 23 basket is one of them "until we get a numer dividable by 3 this number will be 60 and the fifth basket will be the wanted one " 13 "

Notice that there are 73 total fruits. For the ratio to equal $1:2$ and still be integral, there must be a multiple of three total number of fruits. The only value for which $73-n$ is divisible by three is $\boxed{13}$ .

limones en la canasta 'i' = ai

naranjas en la canasta 'i' = bi

i: 1: a1+b1=8 2: a2+b2=11 3: a3+b3=13 4: a4+b4=18 5: a5+b5=23

Total=73 A limones B naranjas A+B=73

A'=2 B' (A-aj)=2 (B-bj) 73-aj=3 B-2 bj 73-aj-bj=3B-3bj T'=3*K

multiplo de 3!

Si fuera j=4:

Total'=73-18=55 no es

para j=3: T'=73-13=60 este si puede ser!

para j=2: T'=73-11 no puede ser para j=1: T'=73-8 tampoco

Respuesta: 13